JavaScript - Return the array elements until a selector is matched

	Object.defineProperty(Array.prototype, 'until',{
	/**
	* Return the array elements until a selector is matched
	* @param {Number\|String\|Function} selector
	* @return {Array} A new array that goes from the first element to `selector`
	*
	* Usage:
	* deepEqual([1,2,3,4,5].until(4), [1, 2, 3, 4])
	* deepEqual(['a','b','c','d','e'].until('c'), ['a', 'b', 'c'])
	* deepEqual([{t:'a'},{t:'b'},{t:'c'},{t:'d'}].until(function(o){return o.t == 'c';}), [{t:'a'},{t:'b'},{t:'c'}])
	*
	* Note:
	* Array as selector aren't supported for code brevity. Yet type coercion will work (of course).
	*/

	value:function(selector){
	var m = this.length, i = 0;

	fn = !selector
	? function(){return true;}
	: (
	typeof selector !== 'function'
	? function(x){return x == selector;}
	: selector
	);

	while(!fn(this[i]) && i++ < m);

	return this.slice(0, i+1);
	}
	});

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Francois-Guillaume Ribreau